Name: Smoky Pan-Seared Buffalo Chicken Sandwiches
Prep time: 10 min
Cook time: 30 min
Total time: 40 min
Yield: 1 serving
Ingredients: 5 oz chicken breast; 1 whole whole grain bun; 0.5 tbsp ghee; 1 tbsp buffalo hot sauce; 2 tbsp non-fat greek yogurt; 0.25 tsp dried dill; 0.25 tsp garlic powder; 0.25 whole avocado; 1 leaf romaine lettuce; 2 slice tomato; 0.25 tsp sea salt; 0.25 tsp black pepper

Smoky Pan-Seared Buffalo Chicken Sandwiches

This is an example of a meal that Solin would create to include in your personalized meal plan.

YOUR SOLIN GENERATED RECIPE

Smoky Pan-Seared Buffalo Chicken Sandwiches

Pan-seared chicken breast tossed in zesty buffalo sauce and served on a toasted bun with a creamy yogurt spread for a satisfying crunch.

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NUTRITION

Protein

57g

Fat

22.3g

Carbs

41.6g

SERVINGS

1 serving

INGREDIENTS

5 oz chicken breast

1 whole whole grain bun

0.5 tbsp ghee

1 tbsp buffalo hot sauce

2 tbsp non-fat greek yogurt

0.25 tsp dried dill

0.25 tsp garlic powder

0.25 whole avocado

1 leaf romaine lettuce

2 slice tomato

0.25 tsp sea salt

0.25 tsp black pepper

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PREPARATION

1
Season the chicken breast evenly with sea salt, black pepper, and garlic powder.
2
Heat a cast-iron skillet over medium-high heat and melt the ghee.
3
Sear the chicken breast for 5-7 minutes per side until the internal temperature reaches 165°F and the exterior is golden.
4
In a small ramekin, stir together the Greek yogurt and dried dill to create a clean-eating ranch spread.
5
Remove the chicken from the pan and immediately toss it in the buffalo hot sauce until thoroughly coated.
6
Place the bun halves cut-side down in the hot skillet for 30-60 seconds until toasted and warm.
7
Assemble the sandwich by layering the yogurt ranch, lettuce, tomato, buffalo chicken, and sliced avocado on the bun.